262 jump, or a miscalculation

De$t!ny · Post by **De$t!ny** » December 2nd, 2005, 9:30 pm

i tried out that jump and seems to be 250-255 units (although didn't use that viewpos thing)...its doable with 125fps and seems really easy with 333fps for some reason

Pwn-Rikku · Post by **Pwn-Rikku** » December 3rd, 2005, 9:30 am

are you all really gd at maths!!

Ownia · Post by **Ownia** » December 3rd, 2005, 10:21 am

lol pythagoros is like 7th grade

Pwn-Rikku · Post by **Pwn-Rikku** » December 3rd, 2005, 11:52 am

whats 7th grade ^^ im year 8.

Neon · Post by **Neon** » December 3rd, 2005, 12:11 pm

yeah lvl 7..so year 9... though the question they give in a high paper make it harder

Pwn-Rikku · Post by **Pwn-Rikku** » December 4th, 2005, 3:47 pm

better make it harder

Ownia · Post by **Ownia** » December 4th, 2005, 3:59 pm

well I'm going to spoil it for you then

If a triangle has sides of length (a,b,c), with sides (a,b) enclosing an angle of 90 degrees ("right angle"), then

aÂ² + bÂ² = cÂ²

Pwn-Rikku · Post by **Pwn-Rikku** » December 4th, 2005, 4:08 pm

i no that already?

Post by **Pedsdude** » December 4th, 2005, 5:10 pm

Pwn-Rikku wrote:well im not one with maths but OMFG leveller is amazing mathamatiction i tryed to make a long word but if thats possible then amazing i can make a 262 wheeeeeeeeeeeeeeeeeeeeeeeeeeee < = i is a pro now
im pretty hyper

It's called Pythagoras - not hard

Maybe you could try and contact noginn Leveller, and ask him to give you the precise distances?

Pwn-Rikku · Post by **Pwn-Rikku** » December 4th, 2005, 5:12 pm

i will learn in school

Post by **Pedsdude** » December 4th, 2005, 5:15 pm

Basically it is a rule with right-angled triangles where if you have 2 lengths you can work out the third.

Opposite (squared) + Adjacent (squared) = Hypotenuse (squared)

Pwn-Rikku · Post by **Pwn-Rikku** » December 4th, 2005, 5:18 pm

i no this stuff.

im clever i take it?

262 jump, or a miscalculation

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